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Sign the absolute value of | X-1 | - | Y-X | x
X0, then Y-X must be positive, so
|x-1|-|y-x|=-(x-1)-(y-x)=1-y
RELATED INFORMATIONS
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- 2. The absolute value of solving equation - 12 + 3x = 18 + 2x
- 3. Solution equation: absolute value 3x + 1 = absolute value 2x-5
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- 10. Weida theorem | x1-x2| X1 and X2 are two steps of the quadratic equation 2x ^ + 5x-3 = 0 with one variable. The process of finding the value of | x1-x2 | is written by WIDA's theorem
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- 12. The absolute value of X + 2 = 3 11 of x-9-2 of X + 2 = (x-1) - 2 of X-2 to solve the equation And 113x - 1 / 12 = 105x plus 1 / 6 4x-3 (20-x) = 6x-7 (9-x)
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- 16. A student forgot to multiply 1 by the least common multiple 12 of each denominator when solving the equation 10-x of 4 / 4 = x-m of 1-3. The result is x = - 1. Please help him find the correct solution of the equation
- 17. When solving the equation 10-4-x = 1-3-x-m to remove the denominator, a student forgot to multiply 1 by 12, and the result = - 1 Find the right solution
- 18. Solve the equation: 4 ^ x + 5 ^ x = 2 times (6 ^ x)
- 19. How to solve the equation: x times x times 6 = 54?
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