Weida theorem | x1-x2| X1 and X2 are two steps of the quadratic equation 2x ^ + 5x-3 = 0 with one variable. The process of finding the value of | x1-x2 | is written by WIDA's theorem

Weida theorem | x1-x2| X1 and X2 are two steps of the quadratic equation 2x ^ + 5x-3 = 0 with one variable. The process of finding the value of | x1-x2 | is written by WIDA's theorem

|X1-x2 | = under root [(x1-x2) ^ 2]
=Under root [(x1 + x2) ^ 2-4x1x2]
We get X1 + x2 = - 5 / 2 from Veda's theorem
x1x2=-3/2
So | x1-x2 | = under the root sign [25 / 4 + 6]
=Under root [49 / 4]
=7/2