![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
If the square of the quadratic equation 2x minus 4x plus 3 = 0 is x1, X2, then x2 divided by X1 plus X1 divided by x2 =? .
According to Weida's theorem:
x1+x2=2 …… A
x1*x2=3/2…… B
X2 / X1 + X1 / x2 = (x2 square + X1 Square) / (x1 * x2)
The denominator is directly substituted into B, where formula = 3 / 2
Molecule = B + 2x1 * x2-2x1 * x2 = (x1 + x2) square - 2x1 * x2 = 4-3 = 1
So the result is 2 / 3
RELATED INFORMATIONS
- 1. Let X1 and X2 be the two roots of the equation 2x + 4x-3, then (x1 + 1) (x2 + 1) and X1 + x2
- 2. Weida theorem | x1-x2| X1 and X2 are two steps of the quadratic equation 2x ^ + 5x-3 = 0 with one variable. The process of finding the value of | x1-x2 | is written by WIDA's theorem
- 3. If (K-4) X2 (the square of x) + (K-2) x + 3Y = 1 is a quadratic equation with respect to x, y, then k =?
- 4. Given the equation x & sup2; + 2 (2-m) x + 3-6M + 0 about X, if two real roots X1 and X2 of the equation satisfy the condition X1 = 3x2, find the value of real number M
- 5. When the fractional equation 2XX − 1 − 5x − 5x + 3 = 0 is solved by the substitution method, if XX − 1 = y, then the original equation can be reduced to () A. 2y2+3y-5=0B. 2y2-5y+3=0C. y2+3y-5=0D. y2-5y+3=0
- 6. If x = 1, the value of cube + 3bx + 4 of algebraic formula 2aX is 5, then what is the value of cube + 3bx + 4 of algebraic formula 2aX when x = - 1?
- 7. The square of a - AB = 3, the square of 4ab-3b = - 2, then the square of a + the square of 3ab-3b is
- 8. The square of a - 3AB + 9b, where a = - 2, B = two-thirds of the value is
- 9. Given A-B = 4, ab = - 1, find the value of formula a + 3ab-b
- 10. Given a + B = 1, A-B = - 3, find the value of a 2 + 3 AB + B 2
- 11. The formula method is used to solve the quadratic equation AX + BX + C = 0 (a is not equal to 0)
- 12. Solve the equation [3x + 1] = 2x-0.5, where [] is the integer sign
- 13. The solution equation | 3x-1 | = 1 | 2x - | 3x-1 | | - x + 3 | - | - X-2 | = 3 "|" is an absolute value
- 14. Solving equation 3x + 2 / 2x + 1 = [3x + 2 / 2x + 1] (absolute value) process
- 15. Solution equation: absolute value 3x + 1 = absolute value 2x-5
- 16. The absolute value of solving equation - 12 + 3x = 18 + 2x
- 17. If the equation with the sign of four absolute values is |||||||||||x-1 |- 2 |- 3 |- 4 | = 0, then its root is
- 18. Sign the absolute value of | X-1 | - | Y-X | x
- 19. The sign | - 2 |, denotes that the absolute value of - 2 is 2, and | + 2 |, denotes that the absolute value of + 2 is 2. If | - x | = 2, then x = 2 or x = - 2. If the equation | - X-1 | = 2 is solved, then X-1 = 2 or X-1 = - 2 can be obtained, and x = 3 or x = - 1 can be obtained by solving the equation respectively. Using the above knowledge, the equation can be solved as follows: | - 2x-1-7 = 0
- 20. The absolute value of X + 2 = 3 11 of x-9-2 of X + 2 = (x-1) - 2 of X-2 to solve the equation And 113x - 1 / 12 = 105x plus 1 / 6 4x-3 (20-x) = 6x-7 (9-x)