In triangle ABC, the corresponding sides of angle a, angle B and angle c are a, B and C respectively, and a & # 178; + B & # 178; + C & # 178; + 338 = 10A + 24B + 26c. Try to judge the shape of triangle ABC and prove it. (practice in the chapter of Pythagorean theorem, find the solution ~)

In triangle ABC, the corresponding sides of angle a, angle B and angle c are a, B and C respectively, and a & # 178; + B & # 178; + C & # 178; + 338 = 10A + 24B + 26c. Try to judge the shape of triangle ABC and prove it. (practice in the chapter of Pythagorean theorem, find the solution ~)

a^2-10a+25+b^2-24b+144+c^2-26c+169=25+144+169
(a-5)^2+(b-12)^2+(c-13)^2=25+144+169
a=10
b=24
c=26
10^2+24^2=26^2
So it is consistent with Pythagorean theorem
So it's a right triangle