It is known that a is equal to 2 times a minus a plus nine fourths, B is equal to 2 times a plus one. For any real number a, compare the size of a and B

It is known that a is equal to 2 times a minus a plus nine fourths, B is equal to 2 times a plus one. For any real number a, compare the size of a and B

A=2*a^2-a+9/4
B=2*a+1
A-B=2a^2-a+9/4-2a-1
=2a^2-3a+5/4
=2(a-3/4)^2+5/4-9/8
=2(a-3/4)^2+1/8
∵(a-3/4)^2≥0
∴A-B>0
So a is greater than B