3 ^ (2x-1) = 4 ^ (x + 1) + 2 ^ (2x-1) hurry up! Wrong. The first one is 3 ^ (2x + 1)

3 ^ (2x-1) = 4 ^ (x + 1) + 2 ^ (2x-1) hurry up! Wrong. The first one is 3 ^ (2x + 1)

x=1/2.
The original equation is equivalent to,
3^(2x+1)=2^(2x+2)+2^(2x-1),
Because 2 ^ (2x + 1) ≠ 0, divide both sides by 2 ^ (2x + 1),
(3/2)^(2x+1)=2+1/4=(3/2)^2,
That is, 2x + 1 = 2,
We get x = 1 / 2