In the expansion of (x-1) (x + 1) 8, the coefficient of X5 is () A. -14B. 14C. -28D. 28

∵ (x-1) (x + 1) 8 = x (x + 1) 8 - (x + 1) 8 ∵ (x-1) (x + 1) 8, in which the coefficient of X5 is equal to the coefficient of X4 minus the coefficient of X5, in which the coefficient of X5 is c84-c85 = 14, so B is selected

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