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∵(x-1)(x+1)8=x(x+1)8-(x+1)8∴(x-1)(x+1)8展開式中x5的係數等於(x+1)8展開式的x4的係數减去x5的係數,∴展開式中x5的係數是C84-C85=14,故選B.
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