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x=1/2. 原方程等價於, 3^(2x+1)=2^(2x+2)+2^(2x-1), 因2^(2x+1)≠0,兩邊同除以2^(2x+1)得, (3/2)^(2x+1)=2+1/4=(3/2)^2, 即2x+1=2, 得x=1/2.
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