The square of X + the square of Y - 8x - 10Y + 41 = 0
x^2+y^2-8x-10y+41=0
x^2-8x+16+y^2-10x+25=0
(x-4)^2+(y-5)^2=0
Because (x-4) ^ 2 > = 0 (Y-5) ^ 2 > = 0
So x-4 = 0, Y-5 = 0
x=4 y=5
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