Sum (1 + a) + (2 + A ^ 2) + (3 + A ^ 3) + +(n + A ^ n) to explain the answer, it's urgent!

Sum (1 + a) + (2 + A ^ 2) + (3 + A ^ 3) + +(n + A ^ n) to explain the answer, it's urgent!

=(1+2+3..+n)+a+a^2+...a^n
=n*(n+1)/2+a(1-a^n)/(1-a)