Try to judge: are triangles with 2n & # 178; + 2n, 2n + 1,2n & # 178; + 2n + 1 sides right triangles? N is greater than 0
(2n & \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\= (2n & # 178; + 2n) & # 178; + (2n + 1) & # 178; so
RELATED INFORMATIONS
- 1. Summation of the fifth series is a compulsory course in mathematics of grade one in senior high school The general term formula of sequence {an} is an = (- 1) ^ (n-1) * (4n-3), and the sum of its first n terms can be obtained It must be adopted in time. Please use the multiply common ratio dislocation subtraction method
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- 11. Sum an = 1 / 3N (n + 1), Sn
- 12. Reading material, mathematician Gauss once studied such a problem in school, 1 + 2 + 3 + +10=? After research, the general conclusion of this problem is 1 + 2 + 3 + +N = n (n + 1), where n is a positive integer. Now let's study a similar problem: 1 × 2 + 2 × 3 + + n(n+1)=? Look at three special equations: 1×2=(1×2×3-0×1×2) 2×3=(2×3×4-1×2×3) 3×4=(3×4×5-2×3×4). After reading this passage, please calculate: (1)1×2+2×3+… +100 × 101; (just write the result) (2)1×2+2×3+… +N (n + 1); (write the calculation process)
- 13. Sum (1 + a) + (2 + A ^ 2) + (3 + A ^ 3) + +(n + A ^ n) to explain the answer, it's urgent!
- 14. 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10.97 + 98 + 99 + 100 =? Gauss's solution
- 15. 19 + 199 + 1999 + 19999 + 1991 + 2 + 3 + 4 + +97+98+99+100.
- 16. Sum: (2-3x5 ^ - 1) + (4-3x5 ^ - 2) + +(2n-3x5 ^ - n) urgent!
- 17. How does Gauss calculate "1 + 2 + 3 +. + 97 + 98 + 99 + 100 = 5050"
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