How does Gauss calculate "1 + 2 + 3 +. + 97 + 98 + 99 + 100 = 5050"

1+2+3+ . +97+98+99+100
=(1+100)+(2+99)+.+(50+51)
=101+101+.+101
There are 50 groups
So,
Original formula = 101 × 50
=5050

RELATED INFORMATIONS

1. Sum: (2-3x5 ^ - 1) + (4-3x5 ^ - 2) + +(2n-3x5 ^ - n) urgent!
2. 19 + 199 + 1999 + 19999 + 1991 + 2 + 3 + 4 + +97+98+99+100．
3. 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10.97 + 98 + 99 + 100 =? Gauss's solution
4. Sum (1 + a) + (2 + A ^ 2) + (3 + A ^ 3) + +(n + A ^ n) to explain the answer, it's urgent!
5. Reading material, mathematician Gauss once studied such a problem in school, 1 + 2 + 3 + +10=? After research, the general conclusion of this problem is 1 + 2 + 3 + +N = n (n + 1), where n is a positive integer. Now let's study a similar problem: 1 × 2 + 2 × 3 + + n（n+1）=? Look at three special equations: 1×2=（1×2×3-0×1×2） 2×3=（2×3×4-1×2×3） 3×4=（3×4×5-2×3×4）. After reading this passage, please calculate: （1）1×2+2×3+… +100 × 101; (just write the result) （2）1×2+2×3+… +N (n + 1); (write the calculation process)
6. Sum an = 1 / 3N (n + 1), Sn
7. Try to judge: are triangles with 2n & # 178; + 2n, 2n + 1,2n & # 178; + 2n + 1 sides right triangles? N is greater than 0
8. Summation of the fifth series is a compulsory course in mathematics of grade one in senior high school The general term formula of sequence {an} is an = (- 1) ^ (n-1) * (4n-3), and the sum of its first n terms can be obtained It must be adopted in time. Please use the multiply common ratio dislocation subtraction method
9. The triangle whose three sides are 2n2 + 2n, 2n + 1, 2n2 + 2n + 1 (n is a positive integer) is () A. Acute triangle B. right triangle C. pure triangle D. acute or right triangle
10. There are two points a and B on the flat ground. A is to the east of mountain D, B is to the southeast of mountain D, and 300 meters in the direction of 25 ° south by west of A. the elevation of C on the top of mountain a is 30 degrees, so as to calculate the mountain height
11. Let n be a positive integer, can (2n + 1) & sup2; - 1 be divisible by 8? Why?
12. The story of the mathematician Gauss Don't be too short or too long. It'd better be about 70 words. I'm going to do a math paper,
13. It is proved that 8 ^ 2n + 1 + 7 ^ (n + 2) is a multiple of 57
14. The story of mathematician Gauss
15. Can (n + 7) 2 - (N-5) 2 be divisible by 24 when n is a natural number? Give reasons
16. Students, have you heard the story of the mathematician Gauss when he was a child? Do you know how he calculated 1 + 2 = ·· + 99 + 100 = 5050 at once It's due tomorrow
17. Let n be a positive integer, try to explain the reason why the power of N + 2 of 2 + 7 can be divided by 5
18. Let n be a positive integer, try to explain the reason why the power of N + 2 of 2 + 7 can be divided by 5
19. What are the stories about the mathematician Gauss? Medium number of words! 5 best!
20. The story about the mathematician Gauss is about 150 ~ 200 words