How to find the limit of (sin (x) - Tan (x)) / x ^ 3 when x tends to 0?

How to find the limit of (sin (x) - Tan (x)) / x ^ 3 when x tends to 0?

∵(sinx-tanx)/x³=(sinx/x)*[(cosx-1)/x²]*(1/cosx)
And lim (x - > 0) (SiNx / x) = 1 (this is an important limit to remember)
LIM (x - > 0) [(cosx-1) / X & sup2;] = LIM (x - > 0) [(- SiNx) / (2x)] (0 / 0 type limit, applying the law of Robida)
=-1/2lim(x->0)(sinx/x)
=-1 / 2 (application critical limit)
lim(x->0)(1/cosx)=1
The original formula = LIM (x - > 0) (SiNx / x) * LIM (x - > 0) [(cosx-1) / X & sup2;] * LIM (x - > 0) (1 / cosx)
=1*(-1/2)*1
=-1/2.