Urgent! A high number topic (related to limit) Let a and B be constants, and limx - > 1 (x ^ 2 + AX-5) / (x-1) = B, then a = (), B = () Would you please write down the process of solving the problem
limX->1 (x^2+ax-5)/(x-1)=b
There must be a zero factor (x-1) in the knower
∴x^2+ax-5=(x-1)(x+5)=x^2+4x-5,∴a=4
b=(1+5)=6
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