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A question about the limit of higher numbers Ax ^ 3-2x ^ 2 + X + 1) / (3x ^ 2-bx + 3) = 2 / 3, x approaches infinity, find a and B The original question is wrong,
Only look at the highest order
Get the original formula = ax ^ 3 / 0 = infinite, so a = 0, otherwise the limit is infinite
So the original formula = - 2x ^ 2 / / 3x ^ 2 = - 2 / 3
Not in line with the title
Please make sure you copy the right question
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