A problem of higher numbers. General solution of differential equation (1) y''=1+(y')^2 (2) xy''+y'=0

(1) Y '' = 1 + (y ') ^ 2 let y' = p y '' = DP / DX, DP / DX = 1 + P ^ 2dp / 1 + P ^ 2 = DX, then we get arctanp = x, P = Tan (x + C1) ∫ y = ∫ Tan (x + C1) DX = - ln| cos (x + C1) | + C2 (2)

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