Find the general solution of the first order differential equation: (2x-y ^ 2) dy YDX = 0, which is the square of Y in brackets

(2x-y & # 178;) dy = ydxdx / dy = 2x / Y-Y, where x is the dependent variable and Y is the independent variable, then DX / dy-2x / y = - y corresponds to the homogeneous equation DX / dy-2x / y = 0, and the general solution is x = CY & # 178; let x = C (y) y & # 178; be the general solution of the original equation, then c '(y) = - 1 / YC (y) = - LNY + C, and the general solution of the original equation is x = (c-lny) y & # 178

RELATED INFORMATIONS

1. Calculus y '= Xe ^ 2x-y, when x = 1 / 2, y = 0, the ball is the special solution of the differential equation
2. Special solution of differential equation y '' = e ^ (2Y) y (0) = y '(0) = 0
3. To find the special solution of the differential equation y '' = e ^ (2Y) when x = 0, y = y '= 0; to write down the additional points of the steps
4. General solution of differential equation y '= y (1-2x) / X
5. Finding the general solution of higher order differential equation y '"= 2x + e ^ x
6. The general solution of the differential equation of Y '+ y = e ^ (2x)
7. General solution of differential equation (2x-y ^ 2) * y '= 2Y? Thank you!
8. General solution of linear differential equation y '- 2Y = - 2x + 3
9. A problem of higher numbers. General solution of differential equation (1) y''=1+(y')^2 (2) xy''+y'=0
10. Find the general solutions of the following differential equations YY '- x + 1 = 0, y'sinx = ylny, cosxsinxdx sinxcosydy = 0,
11. Special solutions of differential equation y '- y = 2xe ^ (2x), y (0) = 1
12. Given that the general formula of a differential equation is y = 2x + C, then the special solution of the differential equation under the initial condition x = O, y = 3 is?
13. The solution of differential equation y '= 2x (y * Y-Y') satisfying initial condition y (0) = 1 is as follows
14. The special solution of the differential equation y '' - y = e ^ x satisfying the condition y (0) = 0, y '(0) = 0 is
15. A special solution to the differential equation y '+ 2XY = e ^ (- x ^ 2) satisfying the initial condition y (0) = 2
16. The special solution of the differential equation y '= e ^ x + y satisfying the condition y (0) = 0 is
17. Find the special solution of the differential equation y '' '= e ^ (- x) satisfying the initial condition y | (x = 1) = y' | (x = 1) = y '' | (x = 1) = 0
18. Make all lines at a point a on the curve y = x * 2 (x is greater than or equal to 0) so that the area enclosed by the curve and X axis is 1 / 12. Try to find the tangent point a and tangent square
19. Make the tangent of the circle (X-6) 2 + y2 = 4 through the origin O & nbsp;, and the length of the tangent is______ ．
20. Make the tangent of circle (x - 6) ^ 2 + y ^ 2 = 4 through origin 0, then the tangent length is