Find the equation of the circle passing through the intersection point and coordinate origin of the circle x ^ 2 + y ^ 2 = 1 and x ^ 2 + y ^ 2-4x + 2 = 0

Find the equation of the circle passing through the intersection point and coordinate origin of the circle x ^ 2 + y ^ 2 = 1 and x ^ 2 + y ^ 2-4x + 2 = 0

X ^ 2 + y ^ 2 = 1 (1) x ^ 2 + y ^ 2-4x + 2 = 0 (2) (1) substitute (2) 4x = 3, x = 3 / 4, y ^ 2 = 7 / 16y = - √ 7 / 4 or y = √ 7 / 4 intersection coordinates (3 / 4, ± √ 7 / 4) on the x-axis, let the center of the circle be (a, 0) a ^ 2 = (A-3 / 4) ^ 2 + 7 / 163a / 2 = 1A = 2 / 3 Center (2 / 3,0) radius r = 2 / 3 circle equation (X-2 / 3) ^ 2 + y ^