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By knowing that the center of circle C is on the straight line L: x-2y-1 = O and passes through the origin and a (2,1), the equation of circle C is obtained
The analytic formula of vertical bisector of OA is y = - 2x + 5 / 2
The simultaneous solution with x-2y-1 = O gives x = 6 / 5, y = 1 / 10
So the intersection B of two lines is (6 / 5,1 / 10)
Radius of circle C ob ^ 2 = (6 / 5) ^ 2 + (1 / 10) ^ 2 = 145 / 100
The equation of circle C is (X-6 / 5) ^ 2 + (x-1 / 10) ^ 2 = 145 / 100
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