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The equation for finding the tangent line of the circle X & # 178; + Y & # 178; = 25 in the direction of point a (5,15)
Let the tangent equation be y = KX + B, and substitute the point a into 15 = 5K + B, B = 15-5ky = KX + 15-5kx & # 178; + Y & # 178; = 25, the center of the circle is (0,0) radius = 5, the distance from the center of the circle to the straight line = radius, i.e. (K & | 178; + 1) = 5 (15-5k) &# 178; = 25 (K & # 178; + 1) 225-150k + 25K & # 178; = 25K & # 178; + 25K =
RELATED INFORMATIONS
- 1. The tangent equation of a point P (- - 3,4) over a circle X & # 178; + Y & # 178; = 25 is I found that my answer is different from the answer. I don't know which one is wrong. So I need a process answer, please
- 2. The tangent equation of a circle whose point passes through a point P (- 4, - 3) on the circle X & # 178; + Y & # 178; = 25 is
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- 8. The tangent equation of a (2,1) - direction circle x ^ 2 + y ^ 2 = 4 is rt
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- 13. Given that the equation of circle is (x-1) + (Y-1) = 1, the coordinates of point P are (2,3), the tangent equation of point P is obtained urgent
- 14. Find the equation of circle C whose center is on the line y = 2x and passes through the origin and point m (3,1)
- 15. Find the equation of circle C whose center is on the line y = 2x and passes through the origin and point m (3,1)
- 16. It is known that a circle passes through the coordinate origin and point P (1,1), and the center of the circle is on the line 2x + 3Y + 1 = 0
- 17. By knowing that the center of circle C is on the straight line L: x-2y-1 = O and passes through the origin and a (2,1), the equation of circle C is obtained
- 18. Find the equation of circle C with the center of circle C on the straight line y = 2x and passing through the origin O and point m (3,1)
- 19. Find the equation of the circle whose center is on the straight line y = - 2x and passes through the origin bar and point a (2, - 1)
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