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Given the equation of the circle and the coordinates of P point, find the tangent equation of the circle passing through P point. (1) (x + 2) 2 + (Y-3) 2 = 13, P (1,5); (2) x2 + y2 = 9, P (3,4)
(1) The tangent is perpendicular to the line between the center of a (- 2,3) and P (1,5); the slope of the tangent is k = - 1kap = - 1 + 25 − 3 = - 32, which is substituted into the oblique expression of the point, Y-5 = - 32 (x-1), that is, the equation of the tangent is 3x + 2y-13 = 0
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