Through point a (4, - 3), make the tangent of circle C (x-3) &# 178; + (Y-1) &# 178; = 1, and find the formula of this tangent Through point a (4, - 3), make the tangent of circle C (x-3) &# 178; + (Y-1) &# 178; = 1, and find the equation of the tangent

Through point a (4, - 3), make the tangent of circle C (x-3) &# 178; + (Y-1) &# 178; = 1, and find the formula of this tangent Through point a (4, - 3), make the tangent of circle C (x-3) &# 178; + (Y-1) &# 178; = 1, and find the equation of the tangent

Let the line be y = KX + B, point a is substituted into - 3 = 4K + B, and B = - 3-4k, so the line is y = kx-3-4k, that is, kx-y-3-4k = 0, center of circle (3,1), radius 1|3k-1-3-4k | / √ (k ^ 2 + 1) = 1, that is (- K-4) ^ 2 = k ^ 2 + 1K ^ 2 + 8K + 16 = k ^ 2 + 1, and the solution is k = - 15 / 8, so y = (- 15 / 8) x-3 + 15 / 215x + 8y-36 = 0 has a special line x =