It is known that a circle passes through the coordinate origin and point P (1,1), and the center of the circle is on the line 2x + 3Y + 1 = 0

It is known that a circle passes through the coordinate origin and point P (1,1), and the center of the circle is on the line 2x + 3Y + 1 = 0

According to the intersection property of straight line and circle, the center of circle is on the perpendicular x + Y-1 = 0 of point O (0,0) and point P (1,1), and then according to the center of circle on the straight line 2x + 3Y + 1 = 0, the coordinates of center C are (4, - 3), so the radius r = | OC | = 5, so the equation of circle is (x-4) 2 + (y + 3) 2 = 25