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求OA的垂直平分線的解析式為y= -2x+5/2 與x-2y-1=o聯立解得x=6/5,y=1/10 所以兩直線交點B為(6/5,1/10) 圓C的半徑OB^2=(6/5)^2+(1/10)^2=145/100 圓C的方程為(x-6/5)^2+(x-1/10)^2=145/100
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