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(1)若切線的斜率存在,可設切線的方程為y-3=k(x-2)即kx-y-2k+3=0則圓心到切線的距離d=|k−1−2k+3|k2+1=1解得k=34故切線的方程為3x-4y+6=0(2)若切線的斜率不存在,切線方程為x=2,此時直線也與圓相切.綜上…
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