If the non-zero function f (x) has f (a + b) = f (a) * f (b) for any real number a and B, and if X1 proves: F (x) > 0

f(x)=f(x/2+x/2)=f(x/2)^2
We get f (x) > = 0
And because f (x) is a nonzero function
So f (x) > 0
As for the condition in the title, when x1
I don't know where to use it

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