Given that the function y = FX defined on R satisfies f (2 + x) = 3f (x), when x ∈ [0,2], f (x) = x-2x, find f (x) when x ∈ [- 4, - 2]=

Given that the function y = FX defined on R satisfies f (2 + x) = 3f (x), when x ∈ [0,2], f (x) = x-2x, find f (x) when x ∈ [- 4, - 2]=

∵ f (x + 2) = 3f (x), and when x ∈ [0,2], f (x) = x & sup2; - 2x, ∵ when x ∈ [- 4, - 2], then x + 4 ∈ [0,2], that is, f (x + 4) = (x + 4) & sup2; - 2 (x + 4), and ∵ f (x + 4) = f [2 + (x + 2)] = 3f (x + 2) = 9F (x) (x ∈ [- 4, - 2]) ∵ f (x) = 1 / 9x & sup2; + 2 / 3x + 8 / 9 (...)