If y = f (x) is a differentiable function and f '(1) = 2, then when x = - 1, the derivative value of function f (- x) is the solution

If y = f (x) is a differentiable function and f '(1) = 2, then when x = - 1, the derivative value of function f (- x) is the solution

Let g = f (- x), then G '(x) = f' (- x) (- x) '= - f' (- x),
g'(-1)=f'(-(-1))=f'(1)=-f'(1)=-2