Use the property of infinitesimal to calculate the following limit (1) Limx ^ 2cos1 / x where x tends to 0 (2) Lim [(arctanx) / x] where x tends to infinity

Use the property of infinitesimal to calculate the following limit (1) Limx ^ 2cos1 / x where x tends to 0 (2) Lim [(arctanx) / x] where x tends to infinity

1. Cos1 / X is a bounded function, so the infinitesimal product is still infinitesimal
limx^2cos1/x=0
2. Arctanx and X are equivalent
So Lim [(arctanx) / x] = LIM (x / x) = 1