Find the limit: limx (1 + 2x) &# 185; divide by the square of X, when x approaches 0, how to find it,

because
LIM (x - > 0) x / X (1 + 2x)
=lim(x->0) x/(1+2x)
=0/(1+2×0)
=0
therefore
Original = ∞

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