If the solution set of X inequality ax + b > 0 is (1, infinity), then the solution set of X inequality (AX + b) (X-2) > 0

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• 1. If the inequality ax ^ 2-6x + A ^ 2 about X
• 2. A1 = 3, an + 1-an = 0, the general term formula of sequence BN satisfies anbn = - 1 ^ n Ask BN =?
• 3. (2 / 3) on the straight line X-Y + 2 = 0, find the general term formula of the sequence {an} {BN}. The second question: let CN = anbn, find the first n terms and TN of the sequence {CN}, and (2 / 3) on the straight line X-Y + 2 = 0, find the general term formula of the sequence {an} {BN}. The second question: let CN = anbn, find the first n terms and TN of the sequence {CN}, and satisfy TN
• 4. If the sum of the preceding terms of sequence an is Sn = 4N ^ 2-N + 2, then the general term formula is
• 5. It is known that the sum of the first n terms of the sequence an is Sn, and an + 2Sn = 4N (n ∈ n +). 1) to find the general term formula 2 of the sequence an It is known that the sum of the first n terms of an is Sn, and an + 2Sn = 4N (n ∈ n +) 1) The general term formula of the sequence an 2) If BN = Nan, find the first n terms of BN and TN
• 6. Let the sum of the first n terms of the sequence {an} be Sn = n square-4n + 1, and find the general term formula
• 7. In the sequence {an}, A1 = 1 / 2, an + 1 = an = 1 / (4N ^ 2-1), find the general term formula of {an}
• 8. Given that the sequence {an} satisfies A1 = 1, (2n + 5) (an + 1) - (2n + 7) an = 4N ^ 2 + 24N + 35 (n ∈ n +), then the general term formula of sequence an is?
• 9. Let the sum of the first n terms be Sn, then S100=
• 10. The general term formula of sequence {an} is an = (- 1) ^ (n-1) * (4n-3), and the sum of the first n terms of sequence {an} can be obtained Solution: when n is even, Sn = (1-5) + (9-13) + (17-21) + ·· + [(- 1) ^ (n-2) (4n-7) + (- 1) ^ (n-1) (4n-3)] = - 4 * (n / 2) = - 2n When n is an odd number Why do you do this? I don't understand. Can you explain it? Thank you I still don't understand
• 11. If the solution set of inequality ax > b about X is (1, positive infinity), then the solution set of inequality (ax-b) / X-2 > 0 about X is (1, positive infinity) The answer is less than negative 1, greater than 2. Why is a greater than zero? If B is negative, it's OK
• 12. How much is infinitesimal multiplied by infinity
• 13. What is infinity multiplied by infinity? What is infinitesimal multiplied by infinitesimal? What is infinity plus infinitesimal?
• 14. Is infinitesimal divided by infinity or infinitesimal?
• 15. On the replacement of equivalent infinitesimal There is a saying in the book: when calculating the limit of the ratio of two infinitesimals, the product factor of the numerator or denominator can be replaced by its equivalent infinitesimal. First, what is the product factor? For example: limx → 0 (e ^ AX-1 + e ^ BX-1) / 2x, can the numerator replace ax BX? It seems that this is not the product factor
• 16. A higher number problem on the Equivalent Infinitesimal Substitution limx→0（sinx-tanx)/{[3√(1+X^2)-1][(1+sinx)-1]} Can the denominator be replaced by "x ^ 2 / 3" and "SiNx / 3" with the equivalent infinitesimal? Because the two equivalent infinitesimals are the same, the subtraction of the molecular part cannot be replaced, so the following steps are not very clear,
• 17. Higher numbers, on equivalent infinitesimals LIM (x approaches 0) 1 / (1-cosx) + 1 / TaNx Can TaNx, (1-cosx) be replaced by the equivalent infinitesimal? If not, why not, can not all multiplication and division be used? 2. LIM (x approaches infinity) [E / (1 + 1 / x) ^ x] ^ x Can (1 + 1 / x) ^ X be replaced by e? If not, why not?
• 18. Let f (x) = | x-1| Tan (x-3) / (x-1) (X-2) (x-3) ^ 2, then f (x) is bounded a (0,1) B (1,2) C (2,3) d (3,4) in which of the following intervals
• 19. It is proved that the function y = (1 / x) sin (1 / x) is unbounded in the interval (0,1], but it is not infinite when x tends to positive infinity
• 20. Find the limit: limx (1 + 2x) &# 185; divide by the square of X, when x approaches 0, how to find it,