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解集是(1,無窮大),即x>1 ax>-b 不等號方向不變 所以a>0, x>-b/a 所以-b/a=1 (ax+b)(x-2)>0 方程(ax+b)(x-2)=0的根是 x=-b/a=1,x=2 所以不等式的解集是x>2,x
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