Find the limit: limx (1 + 2x) 185; divide by the square of X, when x approaches 0, how to find it,
because
LIM (x - > 0) x / X (1 + 2x)
=lim(x->0) x/(1+2x)
=0/(1+2×0)
=0
therefore
Original = ∞
because
LIM (x - > 0) x / X (1 + 2x)
=lim(x->0) x/(1+2x)
=0/(1+2×0)
=0
therefore
Original = ∞