Given cos (a - π / 6) + sin α = 4 √ 3 / 5, then the value of sin (α - 7 π / 6) is My answers are - (4 + 3 √ 3) / 10 and - (4-3 √ 3) / 10, but not in the options Ask for detailed explanation | Math enthusiast | Mathematical art

Given cos (a - π / 6) + sin α = 4 √ 3 / 5, then the value of sin (α - 7 π / 6) is My answers are - (4 + 3 √ 3) / 10 and - (4-3 √ 3) / 10, but not in the options Ask for detailed explanation

cos(a-π/6)+sina=4√3/5=>sin(a+π/6)=4/5∴cos(a+π/6)=±3/5sin(a-7π/6+π/6-π/6)=sin(a+π/6-4π/3)=sin(a+π/6)cos(4π/3)-cos(a+π/6)sin(4π/3)=-sin(a+π/6)cos(π/3)+cos(a+π/6)sin(π/3)=-4/10±3√3/1...

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