If cos (a + b) · cos (a-b) = 1 / 3, then the value of COS ^ 2 a-SiN ^ 2 B is?

If cos (a + b) · cos (a-b) = 1 / 3, then the value of COS ^ 2 a-SiN ^ 2 B is?

Using the formula cos α · cos β = (1 / 2) [cos (α + β) + cos (α - β)]
Cos (a + b) cos (a-b) = 1 / 2 [cos2a + cos2b] = 1 / 3
Because Cos2 α = 2cos ^ 2 α - 1
COS(A+B)COS(A-B)=cos^2A-cos^2B-1=1/3
cos^2A-cos^2B=4/3