It is known that sin θ + cos θ = 1 - √ 3 / 2 (0 1 - √ 3 / 2 is the numerator is 1-radical 3 and denominator is 2

It is known that sin θ + cos θ = 1 - √ 3 / 2 (0 1 - √ 3 / 2 is the numerator is 1-radical 3 and denominator is 2

(sinθ+cosθ)^2=(2-√3)/2
1+2sinθcosθ=(2-√3)/2
1+sin2θ=(2-√3)/2
sin2θ=-√3/2
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