To find the limit 1 / (sin * 2x) - 1 / {x * 2 (COS * 2x)} X -- 0, when the molecule is transformed into x * 2 cos * 2x-sin * 2 x, can we bring cos * 2x equal to 1 into the molecule x*2-sin*2x | Math enthusiast | Mathematical art

To find the limit 1 / (sin * 2x) - 1 / {x * 2 (COS * 2x)} X -- 0, when the molecule is transformed into x * 2 cos * 2x-sin * 2 x, can we bring cos * 2x equal to 1 into the molecule x2-sin2x

Absolutely not. It can only be brought in by multiplication and division. This is equivalent to taking the limit of subtraction of two factors as the subtraction of two factor limits. The condition of this method is that the limits of two factors exist. However, after you open it, the two limits are infinite, so you can't open it. Even if you open it, the answer is completely wrong

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