If α ∈ (0, π) is known, compare 2sin2 α with sin α / 1-cos α

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• 1. It is known that 5sin β = sin (2 α + β), cos α ≠ 0, cos (α + β) ≠ 0
• 2. Given 12sin α + 5cos α = 0, calculate the value of sin α and cos α
• 3. (sinα-sinβ)^2+(cosα-cosβ)^2=4sin^2(α+β)/2
• 4. Tan a + Tan B = - 4, Tan a, Tan B = - 7, find the value of sin ^ 2 (a + b) + 4sin (a + b) - cos ^ 2 (a + b)
• 5. To find the limit 1 / (sin * 2x) - 1 / {x * 2 (COS * 2x)} X -- 0, when the molecule is transformed into x * 2 cos * 2x-sin * 2 x, can we bring cos * 2x equal to 1 into the molecule x*2-sin*2x
• 6. When x approaches infinity, it is better to find the limit of LIM (sin ^ 2x-x) / (COS ^ 2x-x) with formula graph
• 7. Given that a is an acute angle and sin a + cos a = 2 and 3 / 3, then sin a and COS a are
• 8. If sin α + cos α = m, sin α × cos α = n (m ＞ 0, n ＞ 0), then what is the relationship between M and N, What is "^"?
• 9. If sin α + cos α = m, sin α × cos α = n, then what is the relationship between M and N?
• 10. If sin α + cos α = m, sin α × cos α = n (m ＞ 0, n ＞ 0), what is the relationship between M and N,
• 11. Known 0
• 12. If 0 ＜ α ＜ π, 2sin2 α = sin α, then cos (2 α - π / 2)=
• 13. Given cos α = 1 / 4, α∈ (- π / 2,0), find sin (α + π / 4)
• 14. It is known that sin θ + cos θ = 1 - √ 3 / 2 (0 1 - √ 3 / 2 is the numerator is 1-radical 3 and denominator is 2
• 15. A = (COS α, sin α), B = (COS β, sin β), 0 < β < α < π if | A-B | = √ 2 prove a ⊥ B
• 16. It is known that sin α + sin β + sin γ = 0 and cos α + cos β + cos γ = 0. It is proved that cos ^ 2 α + cos ^ 2 β + cos ^ 2 γ is the fixed value
• 17. Given sin β + sin2 β = a, cos β + Cos2 β = B, prove (A & sup2; + B & sup2;) (A & sup2; + B & sup2; - 3) = 2B
• 18. Verification: 1 / Sin & sup2; a + 1 / cos & sup2; A-1 / Tan & sup2; a = 2 + Tan & sup2; a
• 19. If sin (π 2 + θ) = 35, then cos (π - 2 θ) equals () A. 1225B. −1225C. −725D. 725
• 20. Simplifying sin (- 11 π / 3) + cos (12 π / 5) tan2 π - sec13 π / 5cot (- 5 π / 2)