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2sin2α≤sinα/(1-cosα)證明:若α=π,左右相等若α∈(0,π)sinα>0,1-cosα>0;2sin2α-sinα/(1-cosα)=sinα/(1-cosα)*[-4(cosα)^2+4cosα-1]=-(2cosα-1)^2*sinα/(1-cosα)≤0綜上所述2sin2α≤sinα/(1-co…
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