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證明: |a-b|=√2 即(a-b)²;=2 即a²;+b²;-2a.b=2 ∵a²;=cos²;α+sin²;α=1 b²;=cos²;β+sin²;β=1 ∴1+1-2a.b=2 即a.b=0 ∴a⊥b
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