求證：1/sin²；a+1/cos²；a-1/tan²；a=2+tan²；a

求證：1/sin²；a+1/cos²；a-1/tan²；a=2+tan²；a

證明：
1/sin²；a+1/cos²；a-1/tan²；a
=（sin²；a+cos²；a）/sin²；a*cos²；a-1/tan²；a
=1/sin²；a*cos²；a-1/tan²；a
=1/sin²；a*cos²；a-cos²；a/sin²；a
=（1/sin²；a）[（1/cos²；a）-cos²；a]
=（1/sin²；a*cos²；a）[（1-cos²；a*cos²；a]
=（1/sin²；a*cos²；a）[（1+cos²；a]（1-cos²；a）]
=（1/cos²；a）[1+cos²；a]
=（1/cos²；a）+1
=sec²；a+1
=tan²；a+1+1
=tan²；a+2.

Elden Ring Premiere

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