已知sin(π2+θ)=35,則cos(π-2θ)等於() A. 1225B.−1225C.−725D. 725

已知sin(π2+θ)=35,則cos(π-2θ)等於() A. 1225B.−1225C.−725D. 725

∵sin(π2+θ)=cosθ=35,∴cos(π-2θ)=-cos2θ=1-2cos2θ=1-2×(35)2=725.故選D