Given that the vector a = (COS α, - 2) B = (- 1, sin α) and a ⊥ B, then Tan (2014 π - α)= | Math enthusiast | Mathematical art

Given that the vector a = (COS α, - 2) B = (- 1, sin α) and a ⊥ B, then Tan (2014 π - α)=

Vector a = (COS α, - 2) B = (- 1, sin α) and a ⊥ B
The results show that - cos α - 2Sin α = 0 and Tan α = 1 / 2
tan(2014π-α)=tan（-α）=-tanα=1/2

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