Limx →π (SiNx / x) and limx →1 (1 + 1 / x) ^ X are used to find the limit. The difference between these two formulas and two important limit formulas is explained

limx→π(sinx/x)=0/π=0
limx→1（1+1/x）^x=(1+1/1)^1
These two limits are a / B type, that is, direct substitution type
Two important limits, we should pay attention to the difference of the approaching time of the variable x
lim(x-->0)sinx/x=1
lim(x-->∞) (1+1/x)^x=e

RELATED INFORMATIONS

1. When x tends to 90 degrees, find the limit of [(SiNx) ^ 3-2 (SiNx) ^ 2 + 1] / [sinx-1]
2. The limit of (SiNx ^ - 1 * x ^ 2) / SiNx when x approaches 0
3. The limit of SiNx / (x ^ 2 + x) and SiNx / (x ^ 2 + X + 1) at 0 SiNx / (x ^ 2 + x) and The limit of SiNx / (x ^ 2 + X + 1) at 0
4. When x tends to infinity, what is the limit of function (2x SiNx) / (5x + SiNx)?
5. Find the limit of function (xarcsinxsin1 / x) / SiNx when x tends to 0
6. What is the limit of 2x + SiNx / x-sinx when x tends to positive infinity?
7. Function, y = (2-3 of x) divided by (2-4 times 2 of x)
8. Function, y = (2 times 3 x power + 1) divided by (4 times 3 x power - 3)
9. The range of 1 divided by x power of function 2-3 is
10. Find the range of the function y = 4 x-3 times 2 x-3
11. (x-arcsinx) / x ^ 2sin3x take the limit at x = 0
12. Why is the limit of arcsinx divided by X equal to 1,
13. If cos (π / 6-A) = a, then why is sin (2 π / 3-A) equal to a?
14. Given that the vector a = (COS θ, sin θ), the vector b = (3,1), and a ⊥ B, then the value of Tan θ is______ ．
15. Given that vector a = (Tan α, 1) vector b = (2,1) and vector a ‖ vector B, then sin α · cos α Sin α = 2cos α is calculated
16. Vector a = (sin θ, 2), vector b = (COS θ, 1), vector a parallel, vector B, θ belong to (0, π / 2), (1) find Tan θ (2) Find sin θ and cos θ; (3) If sin (θ - φ) = 3 / 5,0
17. Given that the vector a = (COS α, - 2) B = (- 1, sin α) and a ⊥ B, then Tan (2014 π - α)=
18. Let a = (COS (α + β), sin (α + β)), B = (COS (α - β), sin (α - β), and a + B = (4 / 5,3 / 5) find Tan α
19. 1-9 / 41a ^ 3n-2 B ^ 2n + 3 is a binomial of degree six, and the value of n is obtained 2 if / M + 3 / + (n + 2) ^ 2 = 0, find the coefficients and times of (1) m, N; (2) the monomial MX ^ n + 4Y / 9
20. Given: (x + m) (x + n) = x ^ 2-6x + 8, then 2mn-3m-3n=