Given that vector a = (Tan α, 1) vector b = (2,1) and vector a ‖ vector B, then sin α · cos α Sin α = 2cos α is calculated

RELATED INFORMATIONS

• 1. Given that the vector a = (COS θ, sin θ), the vector b = (3,1), and a ⊥ B, then the value of Tan θ is______ ．
• 2. If cos (π / 6-A) = a, then why is sin (2 π / 3-A) equal to a?
• 3. Why is the limit of arcsinx divided by X equal to 1,
• 4. (x-arcsinx) / x ^ 2sin3x take the limit at x = 0
• 5. Limx →π (SiNx / x) and limx →1 (1 + 1 / x) ^ X are used to find the limit. The difference between these two formulas and two important limit formulas is explained
• 6. When x tends to 90 degrees, find the limit of [(SiNx) ^ 3-2 (SiNx) ^ 2 + 1] / [sinx-1]
• 7. The limit of (SiNx ^ - 1 * x ^ 2) / SiNx when x approaches 0
• 8. The limit of SiNx / (x ^ 2 + x) and SiNx / (x ^ 2 + X + 1) at 0 SiNx / (x ^ 2 + x) and The limit of SiNx / (x ^ 2 + X + 1) at 0
• 9. When x tends to infinity, what is the limit of function (2x SiNx) / (5x + SiNx)?
• 10. Find the limit of function (xarcsinxsin1 / x) / SiNx when x tends to 0
• 11. Vector a = (sin θ, 2), vector b = (COS θ, 1), vector a parallel, vector B, θ belong to (0, π / 2), (1) find Tan θ (2) Find sin θ and cos θ; (3) If sin (θ - φ) = 3 / 5,0
• 12. Given that the vector a = (COS α, - 2) B = (- 1, sin α) and a ⊥ B, then Tan (2014 π - α)=
• 13. Let a = (COS (α + β), sin (α + β)), B = (COS (α - β), sin (α - β), and a + B = (4 / 5,3 / 5) find Tan α
• 14. 1-9 / 41a ^ 3n-2 B ^ 2n + 3 is a binomial of degree six, and the value of n is obtained 2 if / M + 3 / + (n + 2) ^ 2 = 0, find the coefficients and times of (1) m, N; (2) the monomial MX ^ n + 4Y / 9
• 15. Given: (x + m) (x + n) = x ^ 2-6x + 8, then 2mn-3m-3n=
• 16. Prove. 1 + 1 / √ 2 + 1 / √ 3 +. + 1 / √ n
• 17. Proof of 1 / 2-1 / (n + 1) by the method of expansion and contraction
• 18. How to simplify Sn = 4N + n (n-1) / 2 times 6 = 3N ^ 2 + n?
• 19. In the sequence {an}, an = 43-3n, then when Sn takes the maximum value, n=______ ．
• 20. The sum of the first n terms of the arithmetic sequence an is Sn = 3N ^ 2 + BN + C. If A3 = 17, what is A10