Known: x ^ 2n = 5, find the value of (1 / 3x ^ 3n) ^ 2-3 * (x ^ 2) ^ 2n
[(1/3)x^3n]^2-3(x^2)^2n
= (1/9)x^6n-3x^4n
= (1/9)(x^2n)^3-3(x^2n)^2
= (1/9)*5^3-3*5^2
= -550/9
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