If XYZ + XY + YZ + ZX + X + y + Z = 1975, find the natural numbers x, y, Z Process~

XYZ + XY + YZ + ZX + X + y + Z = (XYZ + XY) + (YZ + y) + (ZX + x) + Z = XY (Z + 1) + y (Z + 1) + X (Z + 1) + Z = (Z + 1) (XY + y + X + 1) - 1 = (Z + 1) (x + 1) (y + 1) - 1 = 1975, so 4 * 2 * 247 = 1976

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