Given x + y + Z + XY + XZ + YZ + XYZ = 182 (where x, y, Z are all natural numbers, and x > y > z), find the value of X, y, Z Why do you want + 1 on both sides?

Given x + y + Z + XY + XZ + YZ + XYZ = 182 (where x, y, Z are all natural numbers, and x > y > z), find the value of X, y, Z Why do you want + 1 on both sides?

Both sides are the same + 1
x+y+z+xy+xz+yz+xyz=182
X (1 + y) + y + 1 + Z (1 + x) + YZ (1 + x) = 183, 14, 35, 67
(y+1)(x+1)+z(1+x)+yz(1+x)=183
(x+1)(y+1+z+yz)=183
(x+1)[(y+1)+z(1+y)]=183
(x+1)(y+1)(z+1)=183=1*3*61
x=60 y=2 z=0