As shown in the figure, it is known that the straight line M: y = - 1 / 2x + B intersects with the X axis at a (15,0). Take OA as one side, make a rectangle oabc, B in the first quadrant As shown in the figure, it is known that the straight line M: y = - 1 / 2x + B intersects with the X axis at a (15,0). Take OA as one side, make a rectangle oabc in the first quadrant. BC intersects with the straight line m at point D, connecting OD, and od is perpendicular to the straight line M. (1) calculate the length of OD (2) Fold the rectangle along a straight line n so that point B falls on the coordinate axis F and connect BF. Let BF intersect with the straight line n at point P. if point P just falls on the straight line m, calculate the coordinates of point F

As shown in the figure, it is known that the straight line M: y = - 1 / 2x + B intersects with the X axis at a (15,0). Take OA as one side, make a rectangle oabc, B in the first quadrant As shown in the figure, it is known that the straight line M: y = - 1 / 2x + B intersects with the X axis at a (15,0). Take OA as one side, make a rectangle oabc in the first quadrant. BC intersects with the straight line m at point D, connecting OD, and od is perpendicular to the straight line M. (1) calculate the length of OD (2) Fold the rectangle along a straight line n so that point B falls on the coordinate axis F and connect BF. Let BF intersect with the straight line n at point P. if point P just falls on the straight line m, calculate the coordinates of point F

one
Substituting a (15,0) into the expression of the straight line m, we can get b = 15 / 2
So m: y = - 1 / 2x + 15 / 2
Because od is perpendicular to M
So the slope of OD = 2
So od: y = 2x
Because D is the intersection point of OD and m, we can solve the equations: x = 3, y = 6, that is, D (3,6)
So the length of OD = 3 √ 5
two
According to the calculation in 1, B (15,6)
Because B and F are symmetric with respect to line n, BF and line n intersect at point P
So p is the midpoint of BF
When f is on the x-axis, Let f (F, 0)
So the abscissa of point P = (15 + F) / 2, and the ordinate of point P = 6 / 2 = 3
Because P is a point on M
So 3 = - (15 + F) / 4 + 15 / 2
f=3
So f (3,0)
When f is on the y-axis, Let f (0, f)
So the abscissa of point P = 15 / 2 and the ordinate = (6 + F) / 2
Because P is a point on M
So 3 + F / 2 = - 15 / 4 + 15 / 2
f=3/2
So f (0,3 / 2)